Question

$\int {\left(\sqrt{x}-\frac{1}{\sqrt{x}}\right)}^{2}dx$

Answer 1

$$\begin{gathered} \int {\left(\sqrt{x}-\frac{1}{\sqrt{x}}\right)}^{2}dx \\ =\int \left(x+\frac{1}{x}-2\right)dx \\ =\int xdx+\int \frac{dx}{x}-2\int dx \\ =\frac{x^2}{2}+\ln \left|x\right|-2x+C \end{gathered}$$