X2-1-0y2-4 y-3-0A- bB- cC- aD- d

The correct option is B (c) On solving, we get x=+1, 1 and y= 1, 3 Comparing we get x ≥ y ...

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Addition of Unlike Terms

x2-1=0y2+4 y+...

Question

x $^{2}$ - 1 = 0

y $^{2}$ + 4y + 3 = 0

(a)

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(b)

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(c)

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(d)

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Solution

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