$(x^{2} - 1)$ is a factor of f(x) = $(x^{5} + a x^{4} + b x^{3} + c x^{2} + x + d)$ . The graph of f(x) intersects the Y axis at (0, –3). Find the value of (a + c).

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Solution

The correct option is D 3
$(x^{2} - 1) = (x - 1) (x + 1) i s a f a c t o r o f f (x) .$

So, f(1) = f(-1) = 0

Since graph passes through (0, -3)

f(0) = -3 or d = -3

$∴$ a + b + c = 1 and a - b + c = 5

$∴$ a + c = 3

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