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Question

x211x+a and x214x+2a will have a common factor, if a=

A
24
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B
0,24
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C
3,24
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D
0,3
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Solution

The correct option is B 0,24
a1=1,b1=11,c1=a
a2=1,b2=14,c2=2a
Since, one root common
(a1c2a2c1)2=(a1b2a2b1)(b1c2b2c1)
(2aa)2=(14+11)(22a+14a)
a2=(8a)(3)
a=0;a=24

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