x+2 /2 + y-1 /3 =8 and x-3 /2 + y-1 /3 =8.
Multiply 1st equation by 6 to get:
3(x+2)+2(y-1) =48
=> 3x+6+2y-2=48
=>3x+2y+4 =48
=>3x+2y=44 (1)
Multiplying 2nd equation by 6 to get:
3(x-3)+2(y-1) = 48
=> 3x-9+2y-2 =48
=> 3x+2y-11 = 48
=>3x+2y= 59 (2)
If we subtract (2) from (1) we get 0 = -11 which is absurd
It proves that There is NO SOLUTION for x and y, Answer