X2-29 x-210y 2-28 y -195A- aB- bC- dD- c

The correct option is C (d) x^2 + 29x = 210 x^2 + 29x + 210 = 0 x^2+ 15x + 14x + 210 = 0 [x + 15][x + 14] = 0 x = 15, 14 y^2 + 28y = 195 y^2 + 28y + 195 = ...

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Byju's Answer

Standard IX

Mathematics

Algebraic Identities

x2+29 x=-210y...

Question

$x^{2}$ + 29x = -210

$y^{2}$ + 28y = -195

(a)

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(b)

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(c)

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(d)

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Solution

The correct option is D
(d)

$x^{2}$ + 29x = -210

$x^{2}$ + 29x + 210 = 0

$x^{2}$ + 15x + 14x + 210 = 0

[x + 15][x + 14] = 0

x = -15, -14

$y^{2}$ + 28y = -195

$y^{2}$ + 28y + 195 = 0

$y^{2}$ + 15y + 13y + 195 = 0

[y + 15][y + 13] = 0

y = -15, -13

x = -15, -14

So, clearly, x $\leq$ y

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$x^{2} + 29 x = - 210$

$y^{2} + 28 y = - 195$

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x2 + 29x = -210 y2 + 28y = -195

The correct option is D (d) x2 + 29x = -210 x2 + 29x + 210 = 0 x2+ 15x + 14x + 210 = 0 [x + 15][x + 14] = 0 x = -15, -14 y2 + 28y = -195 y2 + 28y + 195 = 0 y2 + 15y + 13y + 195 = 0 [y + 15][y + 13] = 0 y = -15, -13 x = -15, -14 So, clearly, x ≤ y

$x^{2}$ + 29x = -210

$y^{2}$ + 28y = -195

The correct option is D
(d)

$x^{2}$ + 29x = -210

$x^{2}$ + 29x + 210 = 0

$x^{2}$ + 15x + 14x + 210 = 0

[x + 15][x + 14] = 0

x = -15, -14

$y^{2}$ + 28y = -195

$y^{2}$ + 28y + 195 = 0

$y^{2}$ + 15y + 13y + 195 = 0

[y + 15][y + 13] = 0

y = -15, -13

x = -15, -14

So, clearly, x $\leq$ y