Question

x/2 + 2y/3 = -1 and x - y/3 = 3. Solve the given equations using substitution method. Thank you.

Answer 1

Dear Student,

$$\begin{gathered} \frac{x}{2}+\frac{2y}{3}=-1 \\ \frac{3x+4y}{6}=-1 \\ 3x+4y=-6---\left(i\right) \\ x-\frac{y}{3}=3 \\ 3x-y=9 \\ 3x=y+9--\left(ii\right) \\ U\sin g\left(ii\right)in\left(i\right), \\ 4y+y+9=-6 \\ 5y=-9-6 \\ 5y=-15 \\ y=-3 \\ 3x=y+9 \\ 3x=-3+9 \\ 3x=6 \\ x=2. \end{gathered}$$

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