$x^{2} - 4 x + 4 = 0$ ,does this quadratic equation has same roots?

True

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False

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Solution

The correct option is A True
$b^{2} - 4 a c = (- 4)^{2} - 4 (1) (4) = 16 - 16 = 0$
$b^{2} - 4 a c = 0$
$∴$ Given QE has equal roots

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