The correct option is B x 2yWe know that (a^2 nbsp; b^2) = (a + b)(a b) x^2 4 y^2 = x^2 (2y)^2 = (x + 2y)(x 2y) So, when x^2 4y^2 is divided by ...

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Expansion of (x^2 - y^2)

x2-4 y2 ÷x+2 ...

Question

$(x^{2} - 4 y^{2}) \div (x + 2 y)$ =

x + 2 y

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x - 2 y

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x + 4 y

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x - 4 y

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Solution

The correct option is B $x - 2 y$
We know that
$(a^{2} - b^{2}) = (a + b) (a - b)$

$x^{2} - 4 y^{2}$
$= x^{2} - (2 y)^{2}$
$= (x + 2 y) (x - 2 y)$

So, when $x^{2} - 4 y^{2}$ is divided by $(x + 2 y)$ ,
we get $(x - 2 y)$ .
i.e., $\frac{x^{2} - 4 y^{2}}{(x + 2 y)} = \frac{(x + 2 y) (x - 2 y)}{(x + 2 y)} = (x - 2 y)$

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