$x^{2} + 4 y^{2} + z^{2} + 4 x y - 2 x z - 4 y z$ = $(x + 2 y - z)^{2}$

False

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True

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Solution

The correct option is B True

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Similar questions

Factorise: $4 x y - x^{2} - 4 y^{2} + z^{2}$

(i) $x^{2} + y^{2} + z^{2} - x y + x + y z by x + y - z$

(ii) $x^{2} + 4 y^{2} + z^{2} + 2 x y + x z - 2 y z by x - 2 y - z$

(iii) $x^{2} + 4 y^{2} + 2 x y - 3 x + 6 y + 9 by x - 2 y + 3$

(iv) $9 x^{2} + 25 y^{2} + 15 x y + 2 x - 20 y + 16 by 3 x - 5 y + 4$

(x + 2 y + z)^{2}

(x + 2 y + 3 z)^{2}

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