(x^2-5)(x^2-4)/(x-1) < or equal to 0 find the range of x

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$I f x + \frac{1}{x} = 5, t h e n (x^{3} + \frac{1}{x^{3}}) - 5 (x^{2} + \frac{1}{x^{2}}) + (x + \frac{1}{x})$ is equal to

f (x) = \frac{x^{2} - x + 1}{x^{2} + x + 1}

l i m x \to 0 \frac{3 \sqrt{1 + x^{2}} - 4 \sqrt{1 - 2 x}}{x + x^{2}}

\sqrt{x^{2} + x + 1}

\frac{x^{2} + x + 1}{x^{2} - x + 1}

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