The correct option is C (d) Here, on factorization, x = 2 or 3 amp; y = 1 or 2 So, clearly, x ≤ y ...

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Factorisation by Common Factors

x2+5 x+6=0y2+...

Question

x $^{2}$ + 5x + 6 = 0

y $^{2}$ + 3y + 2 = 0

(a)

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(c)

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(d)

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(e)

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Solution

The correct option is C
(d)

Here, on factorization, x = -2 or -3

& y = -1 or -2 So, clearly, x $\leq$ y

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:

x^{2} + 5 x + 6 = 0

x^{2} - 5 x + 6 = 0

x^{2} + 5 x - 6 = 0

x^{2} - 5 x - 6 = 0

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