The correct option is D (x 3)^2Given: x^2 6x + 9. x^2 6x + 9 can be written as x^2 2× x× 3 + (3)^2 Using the identity (a b)^2=a^2 2ab + b^2 nbsp ...

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Expansion of (a - b)^2

x2-6 x+9=

Question

$x^{2} - 6 x + 9$ =

(x + 3)^{2}

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(x - 3) (x - 4)

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(x - 3) (x + 3)

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(x - 3)^{2}

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Solution

The correct option is D $(x - 3)^{2}$
Given: $x^{2} - 6 x + 9$ .

$x^{2} - 6 x + 9$ can be written as
$x^{2} - 2 \times x \times 3 + (3)^{2}$

Using the identity $(a - b)^{2} = a^{2} - 2 a b + b^{2}$ we get,
$\Rightarrow x^{2} - 6 x + 9$ = $(x - 3)^{2}$

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Similar questions

\int \frac{d x}{(x^{2} - 6 x + 9) \sqrt{x^{2} - 6 x + 4}}

\int \frac{1}{(x^{2} - 6 x + 9) \sqrt{x^{2} - 6 x + 4}} d x

f (x) = \sqrt{x^{2} + 6 x + 9} - \sqrt{x^{2} - 6 x + 9}

f (\frac{456}{123}) - f (- \frac{456}{123})

f (x) = \sqrt{x^{2} + 6 x + 9} - \sqrt{x^{2} - 6 x + 9}

f (\frac{456}{123}) - f (- \frac{456}{123})

x^{2} - 6 x + 9

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