X2 - 7-7 x - 3 then p7-7 - -

p( x ) #160; = x ^ 2 7√( 7 ) #160; + 3 p( 7√( 7 ) #160; ) #160; = (7√( 7 ) ) ^ 2 7√( 7 ) (7√( 7 ) ) + 3 = 343 343 + 3 p( 7√ ...

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Byju's Answer

Standard VIII

Mathematics

Cube-Root of Fractional Numbers

x2 - 7√7 x + ...

Question

$x^{2} - 7 \sqrt{7} x + 3$ then $p (7 \sqrt{7}) = ?$

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Solution

$p (x) = x^{2} - 7 \sqrt{7} + 3 p (7 \sqrt{7}) = {(7 \sqrt{7})}^{2} - 7 \sqrt{7} (7 \sqrt{7}) + 3 = 343 - 343 + 3 p (7 \sqrt{7}) = 3$

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x2−7√7x+3 then p(7√7)=?

p(x)=x2−7√7+3p(7√7)=(7√7)2−7√7(7√7)+3=343−343+3p(7√7)=3

$x^{2} - 7 \sqrt{7} x + 3$ then $p (7 \sqrt{7}) = ?$

$p (x) = x^{2} - 7 \sqrt{7} + 3 p (7 \sqrt{7}) = {(7 \sqrt{7})}^{2} - 7 \sqrt{7} (7 \sqrt{7}) + 3 = 343 - 343 + 3 p (7 \sqrt{7}) = 3$