x^2+7x 10=0 #160;or x^2 7x+10=0 #160; x=7±√(( 7)^2 4× 1× 10)2× 1 #160; x=7± 32 #160; x=5,2 ...

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Byju's Answer

Standard XII

Mathematics

Definition of Relations

- x2 + 7x - 1...

Question

$- x^{2} + 7 x - 10 = 0$

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Solution

$- x^{2} + 7 x - 10 = 0$
or $x^{2} - 7 x + 10 = 0$
$x = \frac{7 \pm \sqrt{(- 7)^{2} - 4 \times 1 \times 10}}{2 \times 1}$
$x = \frac{7 \pm 3}{2}$
$x = 5, 2$

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−x2+7x−10=0

−x2+7x−10=0 or x2−7x+10=0 x=7±√(−7)2−4×1×102×1 x=7±32 x=5,2

$- x^{2} + 7 x - 10 = 0$

$- x^{2} + 7 x - 10 = 0$
or $x^{2} - 7 x + 10 = 0$
$x = \frac{7 \pm \sqrt{(- 7)^{2} - 4 \times 1 \times 10}}{2 \times 1}$
$x = \frac{7 \pm 3}{2}$
$x = 5, 2$