Question

$(x^2+7x+12)÷(x+3)$

• A. $x+4$
• B. $x+7$
• C. $x$
• D. None

Answer 1

The correct option is A $x+4$

• Let us first factorize the numerator of the given division $\frac{x^2+7x+12}{x+3}$ as follows:

$x^2+7x+12=x^2+4x+3x+12=x(x+4)+3(x+4)=(x+3)(x+4)$

Since we have to divide $\frac{x^2+7x+12}{x+3}$, therefore, we will divide $\frac{(x+3)(x+4)}{x+3}$ as shown below:

$\frac{(x+3)(x+4)}{x+3}=x+4$

Hence, $\frac{x^2+7x+12}{x+3}=x+4$.