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Quadratic Formula

x2-8x+9=0

Question

$x^{2} - 8 x + 9 = 0$

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Solution

$x^{2} - 8 x + 9 = 0$
here $a = 1, b = - 8, c = 9$
$x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a} x = \frac{8 \pm \sqrt{64 - 36}}{2} 4 \pm \sqrt{7}$

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Q. The zeros of the equation

x^{2} + 8 x + 9 = 0

Circles	Number of common tangents
I: $x^{2} + y^{2} = 4$ $x^{2} + y^{2} - 8 x + 12 = 0$	a) $0$
II: $x^{2} + y^{2} = 1$ $x^{2} + y^{2} - 2 x - 6 y + 6 = 0$	b) $1$
III: $x^{2} + y^{2} = 16$ $x^{2} + y^{2} - 8 x + 6 y - 56 = 0$	c) $4$
IV: $x^{2} + y^{2} - 2 x - 6 y + 9 = 0$ $x^{2} + y^{2} + 6 x - 2 y + 1 = 0$	d) $3$

Q. The product of all the real roots of

x^{2} - 8 x + 9 - \frac{8}{x} + \frac{1}{x^{2}} = 0

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