x2+ 9X + 20 = 0
Y2+ 5Y + 6 = 0
(a)
(b)
(c)
(d)
(e)
x2 + 9x + 20 = 0
x2 + 4x + 5x + 20 = 0
[x + 4][x + 5] = 0
x = -4, -5
y2 + 5y + 6 = 0
y2 + 3y + 2y + 6 = 0
[y + 3][y + 2] = 0
y = -2, -3 x = -4, -5
So, clearly, x<y
x2 - 1 = 0
y2 + 4y + 3 = 0
x2+5x+6=0
y2+3y+2=0
I.x2−7x+12=0 II.y2−12y+32=0
In the following question, two equations are given. Solve both the equations and mark the corresponding answer, if:
a) x is greater than y
b) x is less than y
c) x is greater than or equal than y
d) x is less than or equal to y
e) x = y or a definite relationship between x & y cannot be established