X 2 O 4 l - 2 XO 2 g - - U -2-1 kcal- S -20 calK -1 at 300 K- Then - G is-A- 2-7 kcalB- 9-3 kcalC- -2-7 kcalD- -9-3 kcal

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Calorimetry

X 2 O 4 l ⟶ 2...

Question

$X_{2} O_{4} (l) ⟶ 2 X O_{2} (g), Δ U = 2.1 k c a l$
$Δ S = 20 c a l K^{- 1}$ at 300 K. Then $Δ G$ is:

2.7 kcal

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-2.7 kcal

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

9.3 kcal

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-9.3 kcal

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

X_{2} O_{4 (l)} \to 2 X O_{2 (g)} Δ U = 2.1 k c a l, Δ S = 20 c a l K^{- 1} a t 300 K

Δ G

X_{2} O_{4} (l) \to 2 X O_{2} (g)

Δ U = 2.1 K c a l,

Δ S = 20 c a l K^{- 1}

Δ G

X_{2} O_{4} (l) \to 2 X O_{2} (g)

Δ U = 2.1 k c a l, Δ S = 20 c a l K^{- 1} a t 300 K

Δ G

X_{2} O_{4} (i) \to 2 X O_{2} (g)

Δ U = 2.1 k c a l, Δ s = 20 c a l K^{- 1}

Δ G

X_{2} O_{4} (l) ⟶ 2 X O_{2} (g)

Δ U = 2.1 k c a l

Δ S = 20 c a l K^{- 1}

Δ G

Join BYJU'S Learning Program