Question

$x^2$ varies directly as $y^3$ and when $x=6$, $y=3$. What is the relationship between x and y?

Answer 1

Since $x^2$ varies directly to $y^3$

$x^2=6^2=36$

$y^3=3^3=27$

Then we have

$\frac{x^2}{y^3}=\frac{36}{27}=\frac{4}{3}$

Hence, $3x^2=4y^3$

Which is the relationship between x and y