Question

$x^2+x+\frac{1}{\sqrt{2}}=0$ Find the value of $x$.

Answer 1

$x^2+x+\frac{1}{\sqrt{2}}$

$\frac{-1\pm \sqrt{1-\frac{4}{\sqrt{2}}}}{2}=\frac{-1\pm \sqrt{1-2\sqrt{2}}}{2}$

$=\frac{-1\pm i\left(1.3521\right)}{2}-0.5\begin{array}{c}\end{array}i\left(0.6760\right)$

$x_1=-0.5+0.67i$

$x_2=-0.5-0.67i$