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Question

x2+y2=a2 and (xc)2+y2=b2 are two intersecting circles. lf a, b, c are the sides BC, CA, AB of ΔABC. lf p1,p2,p3 are the altitudes through A,B,C respectively then the length of the common chord is

A
2p1
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B
2p2
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C
2p3
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D
p1
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Solution

The correct option is C 2p3

When two circles intersect at 2 different points the common chord and the line joining the center are perpendicular bisectors.

OC=OD=CD2

CD=2×OC

ABCD

OC is the altitude of the triangle and it passes through C.

OC=P3CD=2P3


847969_33913_ans_a33eed5202654535a40617a0811085fb.png

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