x2 + y2 ∓ 2kx ∓ 2ky + k2 is a set of circles. Which of the following statements are true about them?
All of them touches x-axis
All of them touches y-axis
The radius of all the circles are same
We will go through each option and check if it is satisfied.
A) All of them touches x-axis
We know that x2+y2+2gx+2fy+c=0 touches x-axis if g2=c
In our case g2 = (∓ k)2 = k2 = c
⇒ All of them touches x-axis
B) similarly, the condition to touch the y-axis isf2 = c
In our casef=∓ k and c=k2
f2 = (∓ k2) = k2 = c
⇒ All of them touches y-axis also
C) They are concentric
The centre of x2 + y2 + 2gx + 2fy + c = 0 is (−g,−f)
So the centres of x2 + y2 ∓2kx ∓2ky + k2
Are (k,k),(−k,k),(−k,−k)and(k,−k)
All these have different centres
D) The radius of the x2 + y2 + 2gx + 2fy + c = 0 is given by √g2 + f2 − c
In our case,y=√(∓ k)2 + (∓ k)2 − k2
=√k2
=|k|
⇒ Radius is same for all the circles