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Question

x2 + y2 2kx 2ky + k2 is a set of circles. Which of the following statements are true about them?


A

All of them touches x-axis

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B

All of them touches y-axis

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C

They are concentric

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D

The radius of all the circles are same

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Solution

The correct options are
A

All of them touches x-axis


B

All of them touches y-axis


D

The radius of all the circles are same


We will go through each option and check if it is satisfied.

A) All of them touches x-axis
We know that x2+y2+2gx+2fy+c=0 touches x-axis if g2=c
In our case g2 = ( k)2 = k2 = c
All of them touches x-axis

B) similarly, the condition to touch the y-axis isf2 = c
In our casef= k and c=k2
f2 = ( k2) = k2 = c
All of them touches y-axis also

C) They are concentric
The centre of x2 + y2 + 2gx + 2fy + c = 0 is (g,f)
So the centres of x2 + y2 2kx 2ky + k2
Are (k,k),(k,k),(k,k)and(k,k)

All these have different centres

D) The radius of the x2 + y2 + 2gx + 2fy + c = 0 is given by g2 + f2 c

In our case,y=( k)2 + ( k)2 k2

=k2

=|k|

Radius is same for all the circles


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