Question

$(x^3+2x^2+3x)÷2x$ = ___________.

• A. $x^2+2x+3$
• B. $\frac{1}{2}(x^2+2x+3)$
• C. $2x^2+2x+3$
• D. $2x^2+2x+6$

Answer 1

The correct option is B $\frac{1}{2}(x^2+2x+3)$

Given,$(x^3+2x^2+3x)÷2x$
$\Rightarrow$$\frac{x^3+2x^2+3x}{2x}$
= $\frac{x^3}{2x}+\frac{2x^2}{2x}+\frac{3x}{2x}$
= $\frac{{\mathrm{x/}}^3}{2\mathrm{x/}}+\frac{\text{/}2x^2}{\text{/}2x}+\frac{3\mathrm{x/}}{2\mathrm{x/}}$
= $\frac{x^2}{2}+x+\frac{3}{2}$
This can be written as $\frac{1}{2}(x^2+2x+3)$