(x^3 2x^2+5x 7)(2x 3) =(2x 3)(x^3 2x^2+5x 7) =2x(x^3 2x^2+5x 7) 3(x^3 2x^2+5x 7) =2x× x^3 2x× 2x^2+2x× 5x 2x× 7 3× x^3 3× ( 2x^2) 3× 5x 3× ( 7) =2x^4 4x^3+1 ...

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Byju's Answer

Standard VIII

Mathematics

Multiplication of Any Polynomial

x3-2x2+5x-72x...

Question

$(x^{3} - 2 x^{2} + 5 x - 7) (2 x - 3)$

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Solution

$(x^{3} - 2 x^{2} + 5 x - 7) (2 x - 3) = (2 x - 3) (x^{3} - 2 x^{2} + 5 x - 7) = 2 x (x^{3} - 2 x^{2} + 5 x - 7) - 3 (x^{3} - 2 x^{2} + 5 x - 7) = 2 x \times x^{3} - 2 x \times 2 x^{2} + 2 x \times 5 x - 2 x \times 7 - 3 \times x^{3} - 3 \times (- 2 x^{2}) - 3 \times 5 x - 3 \times (- 7) = 2 x^{4} - 4 x^{3} + 10 x^{2} - 14 x - 3 x^{3} + 6 x^{2} - 15 x + 21 = 2 x^{4} - 4 x^{3} - 3 x^{3} + 10 x^{2} + 6 x^{2} - 14 x - 15 x + 21 = 2 x^{4} - 7 x^{3} + 16 x^{2} - 29 x + 21$

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Similar questions

Q. Simplify:
(x³ − 2x² + 5x − 7)(2x − 3)

Q. If

2 (x^{2} + 1) = 5 x

, find

x^{3} - \frac{1}{x^{3}}

Factorise: $x^{3} - 2 x^{2} - 5 x + 6$

Q. Factorise the polynomial:

x^{3} + 2 x^{2} + 5 x + 10

Q. Solve :

f (x) = (x^{3} - 2 x^{2} - 5 x + 6) < 0

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(x3−2x2+5x−7)(2x−3)

(x3−2x2+5x−7)(2x−3)=(2x−3)(x3−2x2+5x−7)=2x(x3−2x2+5x−7)−3(x3−2x2+5x−7)=2x×x3−2x×2x2+2x×5x−2x×7−3×x3−3×(−2x2)−3×5x−3×(−7)=2x4−4x3+10x2−14x−3x3+6x2−15x+21=2x4−4x3−3x3+10x2+6x2−14x−15x+21=2x4−7x3+16x2−29x+21

$(x^{3} - 2 x^{2} + 5 x - 7) (2 x - 3)$