(x-3)(x-7)(x-12)<0 solve for real x in equalities

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\frac{3 x^{2} - x - 2}{x^{2} - 7 x + 12} \div \frac{3 x^{2} - 7 x - 6}{x^{2} - 4}

x

\frac{7 x - 1}{2} < - 3, \frac{3 x + 8}{5} + 11 < 0

Solve for x and y:

$3 x - 5 y - 19 = 0, - 7 x + 3 y + 1 = 0.$

x^{2} - 7 x + 12 = 0

x^{2} + 7 x + 12 = 0

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