MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Factorising a Binomial

x3 y2-z x2 y+...

Question

$x^{3} y^{2} - z x^{2} y + x^{4} y^{3} =$ $\times (x y - z + x^{2} y^{2})$

A

x y

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

x^{2} y

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

x y^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

x^{2} y^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $x^{2} y$
$x^{3} y^{2} - z x^{2} y + x^{4} y^{3}$
We can take $x^{2} y$ as common from the given expression.
We get $x^{2} y (x y - z + x^{2} y^{2})$

Suggest Corrections

thumbs-up

0

Similar questions

x^{3} y^{2} - z x^{2} y + x^{4} y^{3} =

\times (x y - z + x^{2} y^{2})

Factorise: $x^{3} y^{2} - z x^{2} y + x^{4} y^{3}$

Q. If two positive integers a and b are written as

a = x^{3} y^{2}

b = x y^{3}; x, y

are prime numbers , then HCF(a,b) is

(a) xy (b) xy² (c) x³y³ (d) x²y²

Q. Question 6
If two positive integers a and b are written as

a = x^{3} y^{2} a n d b = x y^{2}

where x, y are prime numbers, then HCF (a, b) is

A)

x y

x y^{2}

x^{3} y^{3}

x^{2} y^{2}

Q. More than One Answer Type
एक से अधिक उत्तर प्रकार के प्रश्न

If a = x⁴y³ and b = xy³z, where x, y and z are prime numbers, then which of the following is/are correct?

यदि a = x⁴y³ तथा b = xy³z, जहाँ x, y व z अभाज्य संख्याएं हैं, तब निम्न में से कौनसा/कौनसे विकल्प सही है/हैं?

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Factorising a Binomial

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Factorising a Binomial

Standard VII Mathematics

Join BYJU'S Learning Program

CrossIcon