x^4 5x^2+4 lt;0 (x^2 1)(x^2 4) lt;0 (x 1)(x+1)(x 2)(x+2) lt;0 x∈ ( 2, 1)∪ (1,2) ...

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Laws of Exponents for Real Numbers

x4 - 5x2 + 4 ...

Question

$x^{4} - 5 x^{2} + 4 < 0$

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Solution

$x^{4} - 5 x^{2} + 4 < 0 ⟹ (x^{2} - 1) (x^{2} - 4) < 0 ⟹ (x - 1) (x + 1) (x - 2) (x + 2) < 0 ⟹ x \in (- 2, - 1) \cup (1, 2)$

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