X={ 4^n-3n-1,n belongs to N} Y={ 9(n-1),n belongs to N} Find X union Y

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If $X = {4^{n} - 3 n - 1 : n \in N}$ and $Y = {9 (n - 1) : n \in N},$ then show that $X \cap Y = X .$

X = {4^{n} - 3 n - 1 : n \in N}

Y = {9 (n - 1) : n \in N},

X \cup Y

If X = { $4^{n}$ - 3n - 1 : n ∈ N} and Y = { 9(n-1) : n ∈ N}, then

X ∪ Y is equal to

X = {4^{n} - 3 n - 1; n \in R}

Y = {9 (n - 1); n \in N}

X \cap Y =

X = {4^{n} - 3 n - 1 : n \in N} & Y = {9 (n - 1) : n \in N}

N

X \cup Y

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