x-4x=4+3

Open in App

Solution

x - 4x = 4+3

take x outside

x(1-4) = 7
X x (-3) =7

X = -7/3

Like if satisfied

Suggest Corrections

Similar questions

(7 - 4 \sqrt{3})^{x^{2} - 4 x + 3} + (7 + 4 \sqrt{3})^{x^{2} - 4 x + 3} = 14

x

\frac{\sqrt{4 x + 1} + \sqrt{x + 3}}{\sqrt{4 x + 1} - \sqrt{x + 3}} = \frac{4}{1}

\frac{\sqrt{4 x + 1} + \sqrt{x + 3}}{\sqrt{4 x + 1} - \sqrt{x + 3}} = \frac{4}{1}

\int \frac{x^{5} + x^{4} + 4 x^{3} + 4 x^{2} + 4 x + 4}{(x^{2} + 2)^{3}} d x

\frac{\sqrt{4 x + 1} + \sqrt{x + 3}}{\sqrt{4 x + 1} - \sqrt{x + 3}} = \frac{4}{1}

Join BYJU'S Learning Program