$x : 5 a 38 c 15$
$y : 241040 b 20 d$ ; $x$ and $y$ are proportional. Find the sum of $a, b, c, d$

39

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40

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41

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42

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Solution

The correct option is C $41$
$x y = 5 \times 24 = 3 \times 40 = 120 = k$

$\Rightarrow x$ is inversely proportional to $y$ . [because product is constant]

$\Rightarrow 5 \times 24 = 10 a = 3 \times 40 = 8 b = 20 c = 15 d = 120$

$\Rightarrow a = \frac{120}{10} = 12 c = \frac{120}{20} = 6$

$\Rightarrow b = \frac{120}{8} = 15 d = \frac{120}{15} = 8$

$\Rightarrow a + b + c + d = 12 + 15 + 6 + 8 = 41$

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