The correct option is C x+y=7
Let us consider x + 2y, on substituting x = 5 and y = 2, we get;
5 + 2(2) = 5 + 4 = 9 ≠ 7
So, (5, 2) is not a solution of x+2y=7.
Now, let us consider 5x + 2y, on substituting x = 5 and y = 2; we get,
(5×5)+(2×2)=25+4=29≠7
So, (5, 2) is not a solution of 5x + 2y = 7.
Let us consider x + y, on substituting x = 5 and y = 2, we get 5 + 2 = 7.
So, (5, 2 ) is a solution of x + y = 7.
Let us consider 5x + y, on substituting x = 5 and y =2, we get;
(5×5)+2=25+2=27≠7
So, (5, 2) is not a solution of 5x + y = 7.