$x = 5, y = 3 a n d z = - 8$ find the value of $x^{3} + y^{3} + z^{3} - 3 x y z$

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Solution

The correct option is C $0$
$x = 5, y = 3$ and $z = - 8$

$x^{3} + y^{3} + z^{3} - 3 x y z = (x + y + z) (x^{2} + y^{2} + z^{2} - x y - y z - z x)$

$= (5 + 3 - 8) (x^{2} + y^{2} + z^{2} - x y - y z - z x)$

$= (0) (x^{2} + y^{2} + z^{2} - x y - y z - z x)$

$= 0$

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