x-6 is the factor of $p (x) = x^{2} + x - 42$ . Because

Quadratic equation

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42 is divisible by 6

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p(6)= 0

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x-6 is linear polynomial

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Solution

The correct option is C
p(6)= 0

As per factor theorem, x-6 is in the form x-a . a=6

If p(a)= p(6)= 0, then x-6 is the factor

We can see that p(6)=0

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Similar questions

What are the factors of polynomial p(x) = x² + x - 6

Use the Factor Theorem to determine whether g(x) is a factor of p(x) in each of the following cases:
(i) p(x)=2 $x^{3}$ + $x^{2}$ −2x−1,g(x)=x+1
(ii) p(x)= $x^{3}$ +3 $x^{2}$ +3x+1,g(x)=x+2
(iii) p(x)= $x^{3}$ −4 $x^{2}$ +x+6,g(x)=x−3

Q. Question 2
Use the Factor Theorem to determine whether g(x) is a factor of p(x) in each of the following cases:

(i) p (x) = 2 x^{3} + x^{2} - 2 x - 1, g (x) = x + 1

(i i) p (x) = x^{3} + 3 x^{2} + 3 x + 1, g (x) = x + 2

(i i i) p (x) = x^{3} - 4 x^{2} + x + 6, g (x) = x - 3

Q. Factors of

(42 - x - x^{2})

are

Q. Factors of

(42 - x - x^{2})

are:

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x-6 is the factor of p(x)=x2+x−42 . Because

The correct option is C p(6)= 0 As per factor theorem, x-6 is in the form x-a . a=6 If p(a)= p(6)= 0, then x-6 is the factor We can see that p(6)=0

x-6 is the factor of $p (x) = x^{2} + x - 42$ . Because

The correct option is C
p(6)= 0

As per factor theorem, x-6 is in the form x-a . a=6

If p(a)= p(6)= 0, then x-6 is the factor

We can see that p(6)=0