x = 6, y = $\frac{- 3}{2}$ is the solution of the equation 3x + 4y - 12 = 0. If true enter 1 else 0.

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Solution

Given equation: 3x + 4y - 12 = 0
$⟹ 3 x + 4 y = 12 ⟹ 4 y = 12 - 3 x ⟹ y = \frac{12 - 3 x}{4}$
Check for x = 6 and $y = \frac{- 3}{2}$ for the solution of given equation:
We have, LHS = 3x + 4y - 12
$⟹ 3 x + 4 y = 12 = 3 (6) + 4 (\frac{- 3}{2}) - 12 = 18 - 6 - 12 = 0 = R H S$
Hence, x = 6 and $y = \frac{- 3}{2}$ is the solution of given equation.

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