$(x + a) (x + b)$ =.

x^{2} + (a + b) + a b

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x^{2} + (a + b) x + a b

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x^{2} + (a x + b) + a b

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Solution

The correct option is B $x^{2} + (a + b) x + a b$
Here, we are using distributive property of multiplication.
$(x + a) (x + b)$
= $x (x + b) + a (x + b)$
= $x^{2} + b x + a x + a b$
= $x^{2} + (a + b) x + a b$

$∴$ $(x + a) (x + b)$ = $x^{2} + (a + b) x + a b$

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