$x$ and $\frac{8}{9}$ are the additive inverse of each other. Then the value of $x$ is

\frac{- 8}{9}

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\frac{- 4}{9}

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\frac{- 5}{9}

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\frac{- 7}{9}

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Solution

The correct option is A $\frac{- 8}{9}$
$\frac{- 8}{9} + \frac{8}{9} = 0$
Thus $\frac{- 8}{9}$ and $\frac{8}{9}$ are additive inverse of each other.
$∴$ the value of $x$ is $\frac{- 8}{9}$

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(\frac{- 3}{7}) + \frac{1}{9} = \frac{1}{9} + (\frac{- 3}{7})

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8 + \frac{7}{10} = \frac{7}{10} + 8

(\frac{- 7}{15}) + 0 = \frac{- 7}{15} = 0 + (\frac{- 7}{15})

\frac{2}{5} + (\frac{- 2}{5}) = 0

\frac{2}{8}

\frac{- 5}{9}

Write the additive inverse of each of the following:

(i) (ii) (iii) (iv) (v)

919829873987649876559876546987654

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