x and y are the sides of two squares such that y=x−x2. The rate of change of area of the second square with respect to that of the first square is
2x2+3x2+1
3x2+2x2−1
2x2−3x+1
3x2+2x+1
Let A=x2 and B=y2=(x−x2)2 ∴dBdA=dBdxdAdx=2(x−x2)(1−2x)2x=(1−x)(1−2x)=2x2−3x+1
If x and y are the sides of two squares such that y=x−x2, then find the rate of change of the area of second square with respect to the area of first square.