X and Y are two cylinders of the same height. The base of X has diameter that is half the diameter of the base of Y. If the height of X is doubled, the volume of X becomes:
Half the volume of Y
Let the height of X and Y be `h', and their radii be r and 2r respectively.
Then, volume of X = πr2h and volume of Y = π (2r)2, h = 4πr2h
New height of X = 2h
So, new volume of X = πr2(2h) = 2πr2h=12(4π2h)=12volumeofY