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Question

X and Y are two points on equal sides AB and AC of the triangle ABC such that AX = BY then the three conditions for ∆AXC ≅ ∆AYB are


A

CX = BY, ∠AXY = ∠AYX, AX = AY

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B

AX = BY, ∠ACB = ∠ABC, BC = BC

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C

AB = AC, AX = AY, BC = BC

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D

AX = AY, ∠A = ∠A, AC = AB

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Solution

The correct option is D

AX = AY, ∠A = ∠A, AC = AB


The triangles are congruent by SAS condition of congruency.

Hence, AX = AY, ∠A = ∠A, AC = AB


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