Question

X and Y start moving towards each other from two places 200 m apart. After walking 60 m. Y turns left and goes 20 m, then he turns right and goes 40 m. He then turns right again and comes back to the road on which he had started walking. If X and Y walk with the same speed, what is the distance between them now?

• A. 20 m
• B. 30 m
• C. 40 m
• D. 50 m

Answer 1

The correct option is C 40 m

Clearly Y moves 60 m from Q upto A, the 20 mupto B, 40 m upto C and then upto D

$So,AD=BC=40m$

$QD=(60+40)m=100m$

Since X and Y travel with the speed, X will travel the same distance along as Y travels in the same time

$i.e.(60+20+40+20)=140m$

So, X travels 140 m upto A.

$\therefore$ Distance between X and Y

$=AD=(100-60)m=40m$