$(x)$ $C H_{3} - O | | S | | - O O - H$ $(y)$ $C H_{3} - O | | C - O - H$ $(z)$ $C H_{3} - O H$
Set the following in increasing order of their $p K_{a}$ values.

y < x < z

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x < y < z

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

y < z < x

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x < z < y

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $x < y < z$
Since $x$ and $y$ are stabilized by resonance, they have higher $K_{a}$ values than $Z$ . Further $x$ is more stabilized than $y$ owing to one more resonance structure.
Hence, order of $K_{a}$ is $x > y > z$
Here the $K_{a}$ , less is $p K_{a} [∵ p K_{a} = - log K_{a}]$
$∴$ Order of $p K_{a}$ is $x < y < z$

Suggest Corrections

Similar questions

H_{2} (g) + V_{2} O_{5} (s) \to V_{2} O_{3} (s) + H_{2} O (l)

Let the coefficients for the given reaction be as follows:

w H_{2} (g) + x V_{2} O_{5} (s) \to y V_{2} O_{3} (s) + z H_{2} O (l)

What will be the values of w, x, y and z so that the reaction is balanced?

Q. Set the following in increasing order of their

p^{K_{a}}

values

(x) C H_{3} O | | S | | O O H (y) C H_{3} O | | C O H (z) C H_{3} O H

In the given reaction

$5 H_{2} O_{2} + x C l O_{2} + 2 O H^{-} \to y C l^{-} + z O_{2} + 6 H_{2} O$

The values of x, y and z are:

In the given figure, $∠ X = 62 º, ∠ X Y Z = 54 º$ . If YO and ZO are the bisectors of $∠ X Y Z$ and $∠ X Z Y$ respectively of ΔXYZ, find $∠ O Z Y$ and $∠ Y O Z$ .

Q. Arrange the following in increasing order of their

p K_{a}

values.
(x)

(y)

(z)

C H_{3} - O H

Join BYJU'S Learning Program

(x) CH3−O||S||−OO−H (y) CH3−O||C−O−H (z) CH3−OHSet the following in increasing order of their pKa values.

The correct option is B x<y<zSince x and y are stabilized by resonance, they have higher Ka values than Z. Further x is more stabilized than y owing to one more resonance structure.Hence, order of Ka is x>y>z Here the Ka, less is pKa[∵pKa=−logKa]∴ Order of pKa is x<y<z

$(x)$ $C H_{3} - O | | S | | - O O - H$ $(y)$ $C H_{3} - O | | C - O - H$ $(z)$ $C H_{3} - O H$
Set the following in increasing order of their $p K_{a}$ values.