x = −b+√b2−4ac2a, then express the given formula in terms of b.
{(c/x) – ax}/x
( - c - ax2 )/x
{(c/x) + ax}/4
{-(c/x) – x/a}/2
x = −b+√b2−4ac2a
(2ax+b)=√b2−4ac
(2ax+b)2=(b2−4ac)
4a2x2+b2+4axb=b2−4ac
4a2x2+4axb=−4ac
ax2+xb=−c
b = −c−ax2x
If x = −b+√b2−4ac2a, then express the given formula in terms of a.
If b2 – 4ac = 0 then The roots of the Quadratic equation ax2 + bx + c = 0 are given by :