Question

$Xg$ metal gave $Yg$ of its oxide. Hence, equivalent mass of the metal is:

• A. $\left(\frac{X}{Y-X}\right)\times 8$
• B. $\left(\frac{Y-X}{X}\right)\times 8$
• C. $\left(\frac{Y+X}{X}\right)\times 8$
• D. $\frac{X}{Y}\times 8$

Answer 1

The correct option is A $\left(\frac{X}{Y-X}\right)\times 8$

Weight of metal = x gm

Weight of oxide = y gm

Oxygen consumed = y-x gm

Since, (y-x) gm of oxygen combines with x

gm of metal

So, 1 gm of oxygen will combine with = x/

(y-x) gm of metal

Hence, 8 gm of oxygen will combine with =

$\left(\frac{X}{Y-X}\right)\times 8$ gm of metal

This $\left(\frac{X}{Y-X}\right)\times 8$ quantity is the equivalent

weight of metal