Question

$x$ g of the metal gave $y$ g of its oxide. Hence equivalent weight of the metal is:

• A. $\frac{y-x}{x}\times 8$
• B. $\frac{x}{(y-x)}\times 8$
• C. $\frac{x}{y}\times 8$
• D. $\frac{x+y}{x}\times 8$

Answer 1

The correct option is B $\frac{x}{(y-x)}\times 8$

Weight of metal= $x$ gm and weight of oxide= $y$ gm

$\therefore$ Oxygen consumed= $(y-x)$gm

Since $(y-x)$ gm of oxygen combines with $x$ gm of metal

$\therefore 8gm$ of oxygen will combine with $\frac{8x}{y-x}$ gm of metal

Hence equivalent weight of metal= $\frac{x}{y-x}\times 8$