Question

$x$ grams of a metal react with dilute sulphuric acid to form $y$ grams of metal sulphate. The equivalent mass of metal is:

• A. $\frac{x}{y}\times 96$
• B. $\frac{x}{y-x}\times 48$
• C. $\frac{x}{x-y}\times 48$
• D. $\frac{y}{y-x}\times 96$

Answer 1

The correct option is B $\frac{x}{y-x}\times 48$

Eq. of metal $=$ Eq. of Sulphate

$\frac{Wt.ofMetal}{Eq.wt}=\frac{Wt.ofSulphate}{Eq.wt}$

In the y grams of metal sulphate formed, weight of sulphate ions will be equal to $y-x$. Let the equivalent weight of metal be $E$. Since we know that the equivalent weight of sulphate ion is 48,

$\frac{x}{E}=\frac{y-x}{48}$ $\therefore E=$ $\frac{x}{y-x}\times 48$