$X + H_{2} O \to Y + C H_{4}$

In the above reaction a unknown component X on hydrolysis gives Y and methane gas. Identify X and Y.

C a C_{2}, A l (O H)_{3}

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A l_{4} C_{3}, A l (O H)_{3}

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M g C_{2}, M g (O H)_{3}

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None of the above

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Solution

The correct option is A $A l_{4} C_{3}, A l (O H)_{3}$
$A l_{4} C_{3} + 12 H_{2} O \to 4 A l (O H)_{3} + 3 C H_{4}$

So the $x$ and $y$ are $A l_{4} C_{3}, A l (O H)_{3}$ .

Hence option $D$ is correct.

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Similar questions

B e_{2} C + H_{2} O \to B e (O H)_{2} + X

C a C_{2} + H_{2} O \to C a (O H)_{2} + Y

X

Y

Balance the following equations

a)Pb(NO₃)₂ gives PbO +NO₂+O₂

b)NH₃+CuO gives Cu+N₂+H₂O

c)NaOH+H₂SO₄ gives Na₂SO₄ +H₂O

d)Al₄C₃+H₂O gives CH₄+Al(OH)₃

X Y \to B e n z o q u i n o n e

{B e}_{2} C + 4 H_{2} O ⟶ 2 X + {C H}_{4}

X + 2 O H ⟶ Y

(X)

(Y)

B a C_{2} + N_{2} Δ ⟶ (X)

C a C_{2} + N_{2} Δ ⟶ (Y) + C (b l a c k)

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