$[X] + H_{2} S O_{4} ⟶ [Y]$ Colorless gas with irritating smell
$[Y] + H_{2} S O_{4} + K_{2} C r_{2} O_{7} ⟶ G r e e n s o l u t i o n$
[X] and [Y] are:

S O_{3}^{2 -}

S O_{2}

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C l^{-}

H C l

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S^{2 -}

H_{2} S

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C O_{3}^{2 -}

C O_{2}

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Solution

The correct option is D $S O_{3}^{2 -}$ , $S O_{2}$
Option (A) is correct.
$[X] a n d [Y]$ are $S O_{3}^{2 -}$ , $S O_{2}$ .
$[X] + H_{2} S O_{4} ⟶ [Y]$ colorless gas with irritating smell
$[Y] + H_{2} S O_{4} + K_{2} C r_{2} O_{7} ⟶ G r e e n s o l u t i o n$
Sulphite ions give sulphur dioxide gas with sulphuric acid, which turns acidified potassium dichromate to green.
$S O_{3}^{2 -} + H_{2} S O_{4} ⟶ S O_{2} + H_{2} O + S O_{4} 2 -$
$\begin{matrix} 3 S O_{2} & + & K_{2} C r_{2} O_{7} & + & H_{2} S O_{4} & ⟶ & K_{2} S O_{4} & + & C r_{2} (S O_{4})_{3} & + & H_{2} O G r e e n \end{matrix}$

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Similar questions

[x] + H_{2} S O_{4} \to

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[X]+H2SO4⟶[Y] Colorless gas with irritating smell[Y]+H2SO4+K2Cr2O7⟶Greensolution[X] and [Y] are:

$[X] + H_{2} S O_{4} ⟶ [Y]$ Colorless gas with irritating smell
$[Y] + H_{2} S O_{4} + K_{2} C r_{2} O_{7} ⟶ G r e e n s o l u t i o n$
[X] and [Y] are: