X+H+⟶Y+Na++H2O
Y+KCl⟶K2Cr2O7+NaCl Find X and Y.
X=Na2Cr2O7;Y=Na2CrO4
X=Na2Cr2O7;Y=Na2Cr2O7
X=Na2CrO4;Y=Na2Cr2O7
X=Na2Cr2O4;Y=Na2CrO4
2Na2CrO4+2H+⟶Na2Cr2O7+2Na++H2O
Na2Cr2O7+2KCl⟶K2Cr2O7+2NaCl
FeCr2O4+Na2CO3+O2⟶X+Y+CO2 Mention X and Y.
Let n(A−B)=25+x, n(B−A)=2x and n(A∩B)=2x. If n(A) = 2(n(B)) then 'X' is
A+SOCl2→B+SO2+HClX+Na→C+H2B+C→(C2H5)2O+NaCl
Then A and X are respectively
BY←2−Butyne+H2X−→A. A and B are geometrical isomers, A is more symmetrical than B. Then X and Y are