Question

$x$ if the potential to which the outer sphere is raised is $x\times {10}^{3}V$

Answer 1

Let q be the charge on smaller sphere. Then,

$\therefore \frac{K\cdot q}{2}+\frac{K\left(2\right)}{4}=0$ or $q=-1\mu C$

Now $V_{outer}=\frac{K(2-1)\times {10}^{-6}}{4\times {10}^{-2}}$

$=\frac{9\times {10}^9\times {10}^{-6}}{4\times {10}^{-2}}$

$=2.25\times {10}^{5}V$